0.25x^2-23x+360=0

Solution for 0.25x^2-23x+360=0 equation:

0.25x^2-23x+360=0

a = 0.25; b = -23; c = +360;
Δ = b2-4ac
Δ = -232-4·0.25·360
Δ = 169
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{169}=13$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-23)-13}{2*0.25}=\frac{10}{0.5}
=20
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-23)+13}{2*0.25}=\frac{36}{0.5}
=72
$